Contents

- 1 kinetic energy word problems answers
- 1.1 Introduction to kinetic energy word problems:
- 1.2 Solutions to kinetic energy word problems
- 1.3 word problems on kinetic energy for practice
- 1.4 Kinetic and Potential Energy word problems
- 1.5 Kinetic energy problems with answers
- 1.6 Kinetic energy word problems answers
- 1.7 Kinetic energy word problems Results
- 1.7.0.1 Extract All Emails from Any Domain
- 1.7.0.2 Find All Domains on Any IP/ Domain
- 1.7.0.3 Kinetic Energy Word Problems | Online Science Help
- 1.7.0.4 Kinetic and Potential Energy word problems Flashcards
- 1.7.0.5 Kinetic and Potential Energy Problem Set - The Biology Corner
- 1.7.0.6 Kinetic Energy problems and Solutions
- 1.7.0.7 Worksheet - Gravitational Potential Energy & Kinetic
- 1.7.0.8 Examples of Kinetic Energy Problems - with mr mackenzie
- 1.7.0.9 KINETIC AND POTENTIAL ENERGY PROBLEMS: KE = 2 GPE =mgh EPE = 2
- 1.7.0.10 Solutions to some problems on Work and Kinetic Energy

# kinetic energy word problems answers

## Introduction to kinetic energy word problems:

Energy is a capacity to do work. The energy gained or lost due to motion, position or configuration is called mechanical energy. It is of two types. Kinetic energy and potential energy.

Kinetic energy = 1/2 Mv 2

Where M is mass of the body

and v = velocity

Let us see some word problems on kinetic energy with solutions.

## Solutions to kinetic energy word problems

**Problem**: – Given that the displacement of body in meters is a function of time as follows: x=2t 4 + 5. The mass of the body is 2kg. What is the increase in its kinetic energy one second after the start of the motion?

**Solution** : – Velocity = v =dx/dt = d/dx (2t 4 +5) = 8t 3

After one second velocity is 8(1)3 = 8 m/s

Kinetic energy = ½ Mv 2 where M = mass of the body, v = velocity

**Problem**: – A body B_{1} is projected upwards with velocity v_{1}. Another body B_{2} of same mass is projected at an angle 45 degree. Both reach the same height. What is the ratio of their initial kinetic energies ?

**Solution** :- Vertical component of initial velocity of B_{2} is equal to the initial velocity of B_{1}.

**Problem**: – If we throw a body upwards with velocity of 4ms -1 at what height its kinetic energy reduces to half of the initial value? Take g = 10 ms -2 .

**Solution**:- Initial energy = 1/2 M(4) 2 = 8M. Let kinetic energy at a height h be 8 M/2 =4. It will also be equal to the potential energy.

## word problems on kinetic energy for practice

**Problem**: – A block of mass M slides down the surface of a bowl of radius R from its rim to the bottom. What will be the kinetic energy of the block at the bottom? (Answer:- MgR where g is acceleration due to gravity)

**Problem**: – A block is moved from rest through a distance of 4m along a straight line path. The mass of the block is 5kg and the force acting on it is 20 N. If the kinetic energy acquired by the block be 40 J, at what angle to the path the force is acting? (Answer = 60 degree )

**Problem**: – When the mass and speed of a body are doubled, the kinetic energy of the body is? (Answer:- Becomes eight times)

**Problem**: – The momentum of a body is p and its kinetic energy is E. If momentum is doubled, the kinetic energy of the particle is? (Answer:- 4E )

**Problem**: – A machine possesses 80 % efficiency. It raises a mass of 5kg through a certain distance and spends 100 J of energy. If the mass is now released its kinetic energy on reaching the ground will be? (Answer:- 80 Joules )

## Kinetic and Potential Energy word problems

KE= 203.125 KE= 203.125 J

a. How much kinetic energy does the ball have?

b. If the 1.0 kg ball has the same amount of potential energy at the top of its ascent as the amount of kinetic energy, how high did the ball travel?

KE= 0.5 ⋅ 1.0 ⋅ 30(30)

V= √(4,000 ÷ 250) = 4 m/s

KE = ½ x 2.1 kg x (30m/s)2

GPE = 12N x 21 m

KE = ½ x 1120 kg x (40 m/s)2

GPE = 79 N x 20 m

GPE = 190 N x 45 m

GPE = 966 N x 72 m

KE = ½ x 3 kg x (2 m/s)2

2 m/sec. The other had a mass of 4 kilograms and was lifted at a rate of 3 m/sec.

a. Which object had more kinetic energy while it was being lifted?

b. Which object had more potential energy when it was lifted to a distance of 10 meters?

KE = ½ x 2 kg x (2 m/s) 2

KE = ½ x 4 kg x (3 m/s)2

b. The 4 kg object had more potential energy when it was lifted 10 m. GPE = mgh. A greater mass would make a greater GPE.

time you checked, your mass was 60.0 kg.

a. What is your weight in newtons?

b. What is the height of the hill?

c. If you start rolling down this hill, your potential energy will be converted to kinetic energy. At the

bottom of the hill, your kinetic energy will be equal to your potential energy at the top. Calculate

your speed at the bottom of the hill. (Note: KE=PE)

## Kinetic energy problems with answers

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## Kinetic energy word problems answers

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## Kinetic energy word problems Results

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#### Extract All Emails from Any Domain

#### Find All Domains on Any IP/ Domain

#### Kinetic Energy Word Problems | Online Science Help

Introduction to kinetic energy word problems: Energy is a capacity to do work. The energy gained or lost due to motion, position or configuration is called mechanical energy. It is of two types. Kinetic energy and potential energy. Kinetic energy = 1/2 Mv2 Where M is mass of the body and v = velocity Let…

#### Kinetic and Potential Energy word problems Flashcards

Start studying Kinetic and Potential Energy word problems. Learn vocabulary, terms, and more with flashcards, games, and other study tools.

#### Kinetic and Potential Energy Problem Set - The Biology Corner

Practice problems for physics students on potential energy and kinetic energy. These are very simple problems that can be solved without the use of a calculator.

#### Kinetic Energy problems and Solutions

Solutions to kinetic energy problems. Learn how to use the kinetic energy formula

#### Worksheet - Gravitational Potential Energy & Kinetic

A 5-page review worksheet that covers gravitational potential energy (GPE=mgh) AND kinetic energy (KE=1/2MV2) calculations through a set of 10 word problems. Page 1

#### Examples of Kinetic Energy Problems - with mr mackenzie

Examples of Kinetic Energy Problems. The Kinetic Energy (E k) of an object depends on both its mass (m) and its speed (v). What you need to know about Kinetic Energy depends on the paper you are sitting at the time.

#### KINETIC AND POTENTIAL ENERGY PROBLEMS: KE = 2 GPE =mgh EPE = 2

KINETIC AND POTENTIAL ENERGY PROBLEMS: KE = ½ mv2 GPE =mgh EPE = ½ kx2 k=F/x Section 5-2 Pg. 173 #2 Two bullets have the mass of 3 g and 6 g, respectively. Both are fired with a

As it is often said, an equation is not merely a recipe for algebraic problem solving, but also a guide to thinking about the relationship between quantities. Kinetic energy is a scalar quantity; it does not have a direction. Unlike velocity, acceleration, force, and momentum, the kinetic energy of an object is completely described by magnitude

A 3 kg ball is rolling 2 m/s. How much kinetic energy does it have? m = 3 kg v = 2 m/s What are you looking for (what is your unknown)? ?

#### Solutions to some problems on Work and Kinetic Energy

Solutions to some problems on Work and Kinetic Energy Also look at the problems we did in class P10.1. Prepare: P10.3. Prepare: Note that not all the forces in this problem are parallel to the displacement. Equation 10.9 gives the work done by a constant force which is not parallel to the displacement: W =Fdcos(θ), where W is the work done